Showing posts with label Grove HSC 3U Challenge 5. Show all posts
Showing posts with label Grove HSC 3U Challenge 5. Show all posts

Tuesday, 10 May 2016

Grove HSC 3U - Challenge 5, Q23

hey sir also its in challenge 5



$u=\cos x$
$du=-\sin x dx$

Recall $\sin^2x=1-\cos^2x$

So, $I=-\int \sin^2x\, \sin x \,dx$
$I=-\int (1-\cos^2x)\, \sin x \,dx$
$I=-\int (1-u^2)\, du$
$I=-u+u^3/3+c$