Tuesday, 31 May 2016
Grove HSC ch 7 test yourself q4
Juliette Tighe
Tutor Group 39I'm not sure what's wrong but the answers say 5pi/12
you were close, -sin^(-1)(-1/2)=sin^(-1)(1/2) as sin^(-1)x is odd.
and sin^(-1)(1/2)=pi/6 (not pi/3)
then it works.
see written solution.
:-)
Jan
Monday, 30 May 2016
Grove HSC 3U Exercise 5.11 Q3
Help :)
I edited over yours, see below. You were close, just bit magic math happening at the bottom. JH :-)
Sunday, 29 May 2016
Saturday, 28 May 2016
Thursday, 26 May 2016
Wednesday, 25 May 2016
Tuesday, 24 May 2016
Monday, 23 May 2016
Tuesday, 17 May 2016
Sunday, 15 May 2016
Saturday, 14 May 2016
Wednesday, 11 May 2016
Tuesday, 10 May 2016
Grove HSC 3U - Challenge 5, Q23
hey sir also its in challenge 5
$u=\cos x$
$du=-\sin x dx$
Recall $\sin^2x=1-\cos^2x$
So, $I=-\int \sin^2x\, \sin x \,dx$
$I=-\int (1-\cos^2x)\, \sin x \,dx$
$I=-\int (1-u^2)\, du$
$I=-u+u^3/3+c$
$u=\cos x$
$du=-\sin x dx$
Recall $\sin^2x=1-\cos^2x$
So, $I=-\int \sin^2x\, \sin x \,dx$
$I=-\int (1-\cos^2x)\, \sin x \,dx$
$I=-\int (1-u^2)\, du$
$I=-u+u^3/3+c$
Monday, 9 May 2016
Grove HSC 5.11 q2c
You got the sign wrong, its $\Large x-{\sin(2x)\over 2}$ on line 3.
Line 4 correction: $\ldots \Large \left[ { \pi^2\over 2}-{\pi^2\over 8} \right]$
Saturday, 7 May 2016
Thursday, 5 May 2016
Wednesday, 4 May 2016
Tuesday, 3 May 2016
Small angle formula for sin(x)/x etc
This web page explains this really well.
SMALL ANGLE FORMULA FOR SIN(X)/X
SMALL ANGLE FORMULA FOR SIN(X)/X
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